F(x)=2(9x^2-4x+8)-6(3x^2+7x-2)

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Solution for F(x)=2(9x^2-4x+8)-6(3x^2+7x-2) equation: 



(F)=2(9F^2-4F+8)-6(3F^2+7F-2)

We move all terms to the left:

(F)-(2(9F^2-4F+8)-6(3F^2+7F-2))=0



We calculate terms in parentheses: -(2(9F^2-4F+8)-6(3F^2+7F-2)), so:

2(9F^2-4F+8)-6(3F^2+7F-2)

We multiply parentheses

18F^2-18F^2-8F-42F+16+12

We add all the numbers together, and all the variables

-50F+28

Back to the equation:

-(-50F+28)



We get rid of parentheses

F+50F-28=0

We add all the numbers together, and all the variables

51F-28=0

We move all terms containing F to the left, all other terms to the right

51F=28

F=28/51

F=28/51

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